(2x^4+5x^2+5)/(x+2)

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Solution for (2x^4+5x^2+5)/(x+2) equation:


D( x )

x+2 = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x in (-oo:-2) U (-2:+oo)

(2*x^4+5*x^2+5)/(x+2) = 0

(2*x^4+5*x^2+5)/(x+2) = 0 // * x+2

2*x^4+5*x^2+5 = 0

t_1 = x^2

2*t_1^2+5*t_1^1+5 = 0

2*t_1^2+5*t_1+5 = 0

DELTA = 5^2-(2*4*5)

DELTA = -15

DELTA < 0

x belongs to the empty set

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